(2x)^2=(870)-(870*2x)+(870*x^2)

Solution for (2x)^2=(870)-(870*2x)+(870*x^2) equation:

(2x)^2=(870)-(870*2x)+(870x^2)

We move all terms to the left:

(2x)^2-((870)-(870*2x)+(870x^2))=0

We add all the numbers together, and all the variables

2x^2-(870-(+870*2x)+870x^2)=0


We calculate terms in parentheses: -(870-(+870*2x)+870x^2), so:

870-(+870*2x)+870x^2

determiningTheFunctionDomain
870x^2-(+870*2x)+870

We get rid of parentheses

870x^2-870*2x+870

Wy multiply elements

870x^2-1740x+870

Back to the equation:

-(870x^2-1740x+870)


We get rid of parentheses

2x^2-870x^2+1740x-870=0

We add all the numbers together, and all the variables

-868x^2+1740x-870=0

a = -868; b = 1740; c = -870;
Δ = b2-4ac
Δ = 17402-4·(-868)·(-870)
Δ = 6960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6960}=\sqrt{16*435}=\sqrt{16}*\sqrt{435}=4\sqrt{435}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1740)-4\sqrt{435}}{2*-868}=\frac{-1740-4\sqrt{435}}{-1736}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1740)+4\sqrt{435}}{2*-868}=\frac{-1740+4\sqrt{435}}{-1736}
$